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-2x^2+32x-120=0
a = -2; b = 32; c = -120;
Δ = b2-4ac
Δ = 322-4·(-2)·(-120)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8}{2*-2}=\frac{-40}{-4} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8}{2*-2}=\frac{-24}{-4} =+6 $
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